Melting and recasting problems have one golden rule: the VOLUME of metal never changes shape-to-shape, even though the surface area always does.
Study Zone is free for our students — you just need to log in with your WhatsApp number first.
Log in with WhatsApp →The first two chapters of every book are free once you're logged in. To open this one, request an unlock and we'll get back to you on WhatsApp.
Volume measures how much a solid can HOLD; surface area measures how much material would COVER its outside.
📊 The core formulas
| Solid | Volume | Total surface area |
|---|---|---|
| Cube (side s) | s³ | 6s² |
| Cuboid (l, w, h) | l × w × h | 2(lw + wh + hl) |
| Cylinder (radius r, height h) | πr²h | 2πr(r + h) |
Worked example: a cylinder with r=7, h=10 (π=22/7): volume = (22/7)×49×10 = 1540; total surface area = 2×(22/7)×7×(7+10) = 748.
A cone's volume is exactly ONE THIRD of a cylinder with the same base and height — this connection is worth remembering.
📌 Cone and sphere formulas
Cone volume = ⅓ × πr² × h. For r=7, h=6: volume = ⅓×(22/7)×49×6 = 308.
Cone slant height l = √(r² + h²), used for curved surface area = πrl.
Sphere volume = 4/3 × πr³. Sphere surface area = 4πr².
Worked example — slant height: a cone with r=7 and h=24 has slant height l=√(7²+24²)=√625=25. Its curved surface area = πrl = (22/7)×7×25 = 550.
When a solid is melted and recast into a new shape, only the VOLUME stays exactly the same — set the two volume formulas equal to each other.
Worked example: a metal sphere of radius 6 cm is melted and recast into a cylinder of radius 3 cm. Sphere volume = (4/3)π×216 = 288π. Setting this equal to the cylinder's volume πr²h = 9πh gives h = 288÷9 = 32 cm.
12 questions on volume, surface area, and melting & recasting.